Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Matrices

Question:

Match List-I with List-II

List-I

List-II

(A) A square matrix P is said to be non-singular if

(I) $|P| = 0$

(B) A square matrix P is said to be singular if

(II) $PP^T$ is symmetric

(C) If a matrix P is both symmetric and skew-symmetric, then

(III) $|P| ≠ 0$

(D) If P is a square matrix, then

(IV) P is a null matrix

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Correct Answer:

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Explanation:

The correct answer is Option (3) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

List-I

List-II

(A) A square matrix P is said to be non-singular if

(III) $|P| ≠ 0$

(B) A square matrix P is said to be singular if

(I) $|P| = 0$

(C) If a matrix P is both symmetric and skew-symmetric, then

(IV) P is a null matrix

(D) If P is a square matrix, then

(II) $PP^T$ is symmetric

(A) A matrix is said to be non-singular if its determinant is nonzero, i.e. $|P| \ne 0$. This means the matrix has an inverse. → (III)

(B) A matrix is said to be singular if its determinant is zero, i.e. $|P| = 0$. This means the matrix does not have an inverse. → (I)

(C) If a matrix is both symmetric ($P^T = P$) and skew-symmetric ($P^T = -P$), then combining gives $P = -P \Rightarrow 2P = 0 \Rightarrow P = 0$. Hence, it must be a null matrix. → (IV)

(D) For any square matrix $P$, the product $PP^T$ is always symmetric, because $(PP^T)^T = (P^T)^T P^T = PP^T$. → (II)

Final Matching:

(A)–(III), (B)–(I), (C)–(IV), (D)–(II)