Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(III), (C)-(I), (D)-(IV) (A)-(III), (B)-(I), (C)-(IV), (D)-(II) (A)-(I), (B)-(IV), (C)-(II), (D)-(III) |
(A)-(III), (B)-(I), (C)-(IV), (D)-(II) |
The correct answer is Option (3) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
(A) A matrix is said to be non-singular if its determinant is nonzero, i.e. $|P| \ne 0$. This means the matrix has an inverse. → (III) (B) A matrix is said to be singular if its determinant is zero, i.e. $|P| = 0$. This means the matrix does not have an inverse. → (I) (C) If a matrix is both symmetric ($P^T = P$) and skew-symmetric ($P^T = -P$), then combining gives $P = -P \Rightarrow 2P = 0 \Rightarrow P = 0$. Hence, it must be a null matrix. → (IV) (D) For any square matrix $P$, the product $PP^T$ is always symmetric, because $(PP^T)^T = (P^T)^T P^T = PP^T$. → (II) Final Matching: (A)–(III), (B)–(I), (C)–(IV), (D)–(II) |