If 3 tan θ = 2, what is the value of (3sinθ -cosθ)/(3sinθ +cosθ) ?

1 3 $1/\sqrt{3}$ 1/3

1/3

3 tan θ = 2 tan θ = \(\frac{2}{3}\) { we know,  tan A = \(\frac{P}{B}\) } By using pythagoras theorem , P² + B² = H² 2² + 3² = H² H = √13 Now, \(\frac{3 sinθ - cosθ }{3 sinθ + cosθ}\) = \(\frac{3× 2/√13 - 3/√13 }{3 × 2/√13 + 3/√13 }\) = \(\frac{3 }{9 }\) = \(\frac{1}{3}\)