O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
Answer & explanation
Correct answer: option 1
According to the concept
\(\angle\)OQP = \({90}^\circ\)
Hence, OP is the hypotenuse of \(\Delta \)OQP which is a right angled triangle.
Now, OP =√(\( {24 }^{2 } \) + \( {10 }^{2 } \)) = 26 cm
Therefore, the value of OP is 26 cm.