$\int\limits_{1 / 2}^2 \frac{1}{x} \sin \left(x-\frac{1}{x}\right) d x=$

0 1 2 $\sqrt{2}$

0

$I=\int\limits_{1 / 2}^2 \frac{1}{x}\sin \left(x-\frac{1}{x}\right) d x$  ...(1) let $\frac{1}{x}=t$ so $dx=\frac{-1}{t^2}dt$ $⇒I=-\int\limits_{1 / 2}^2\frac{1}{t}\sin \left(t-\frac{1}{t}\right)dt=-\int\limits_{1 / 2}^2 \frac{1}{x}\sin \left(x-\frac{1}{x}\right) d x$   ...(2) so eq. (1) + eq. (2) $2I+0⇒I=0$