CUET Preparation Today
CUET
-- Mathematics - Section B2
Calculus
If $x=a t^2, y=2 a t$, then $\frac{d^2 y}{d x^2}$ is equal to:
$-\frac{1}{2 a t^2}$
$-\frac{1}{2 a t^3}$
$\frac{1}{t^3}$
$\frac{1}{t^2}$
The correct answer is Option (2) → $-\frac{1}{2 a t^3}$
