Three of the following four letter groups are alike in a certain way and one is different. Choose the odd one out.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → FGJNV
Write each letter’s place in the alphabet (A = 1, B = 2, …, Z = 26) and find the jumps from one letter to the next.
Option (1) JKMQY — J (10), K (11), M (13), Q (17), Y (25): jumps +1, +2, +4, +8.
Option (2) FGJNV — F (6), G (7), J (10), N (14), V (22): jumps +1, +3, +4, +8.
Option (3) FGIMU — F (6), G (7), I (9), M (13), U (21): jumps +1, +2, +4, +8.
Option (4) BCEIQ — B (2), C (3), E (5), I (9), Q (17): jumps +1, +2, +4, +8.
Three groups go +1, +2, +4, +8; FGJNV goes +1, +3, +4, +8, so FGJNV is the odd one out.