If $A$ and $B$ are non-singular matrices of same order with $\det(A) = 5$, then $\det(B^{-1}AB)^2$ is equal to
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $5^2$ ##
$|A| = 5$,
$|B^{-1}AB|^2 = (|B^{-1}| \cdot |A| \cdot |B|)^2$
$= |A|^2$
$= 5^2$