CUET Preparation Today
If $A$ and $B$ are non-singular matrices of same order with $\det(A) = 5$, then $\det(B^{-1}AB)^2$ is equal to |
5 $5^2$ $5^3$ $5^5$ |
$5^2$ |
The correct answer is Option (2) → $5^2$ ## $|A| = 5$, $|B^{-1}AB|^2 = (|B^{-1}| \cdot |A| \cdot |B|)^2$ $= |A|^2$ $= 5^2$ |
