ΔPQR is a right angled triangle. ∠Q= 90 degree, PQ = 12 cm, QR = 5 cm. What is the value of cot P-tan R?

5/24 5/6 5/13 0

0

Cot P = \(\frac{5}{12}\) Tan R = \(\frac{5}{12}\) Cot P - tan R = \(\frac{5}{12}\) - \(\frac{5}{12}\) = 0