ΔPQR is a right angled triangle. ∠Q= 90 degree, PQ = 12 cm, QR = 5 cm. What is the value of cot P-tan R?
Answer & explanation
Correct answer: option 4
Cot P = \(\frac{5}{12}\)
Tan R = \(\frac{5}{12}\)
Cot P - tan R = \(\frac{5}{12}\) - \(\frac{5}{12}\) = 0