If $tan x = \frac{10}{17}$, then what is the value of sinx ?
Answer & explanation
Correct answer: option 3
$tan x = \frac{10}{17}$
= $\frac{P}{B}$
P = 10, B = 17
H = $\sqrt{P^2+B^2}$
= $\sqrt{10^2+17^2}$ = $\sqrt{389}$
$sinx= \frac{P}{H}$
= $\frac{10}{\sqrt{389}}$