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If $tan x = \frac{10}{17}$, then what is the value of sinx ? |
$\frac{17}{\sqrt{389}}$ $\frac{7}{\sqrt{389}}$ $\frac{10}{\sqrt{389}}$ $\frac{9}{\sqrt{389}}$ |
$\frac{10}{\sqrt{389}}$ |
$tan x = \frac{10}{17}$ = $\frac{P}{B}$ P = 10, B = 17 H = $\sqrt{P^2+B^2}$ = $\sqrt{10^2+17^2}$ = $\sqrt{389}$ $sinx= \frac{P}{H}$ = $\frac{10}{\sqrt{389}}$ |
