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In the circuit shown in the figure:
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The current through NP is 0.5 A The value of R1 = 40Ω The value of R = 14Ω The potential difference across R = 49 V |
The value of R1 = 40Ω |
In parallel current distribution in inverse ratio of resistance.
R1 = 40Ω Further VNP = 20 V ⇒ VR = 69 - 20 = 49 V R = $\frac{49}{3.5}$ = 19Ω |
