In the circuit shown in the figure:

The current through NP is 0.5 A The value of R1 = 40Ω The value of R = 14Ω The potential difference across R = 49 V

The value of R1 = 40Ω

In parallel current distribution in inverse ratio of resistance. R1 = 40Ω Further VNP = 20 V  ⇒  VR = 69 - 20 = 49 V             R = $\frac{49}{3.5}$ = 19Ω