In the circuit shown in the figure:
Answer & explanation
Correct answer: option 2
In parallel current distribution in inverse ratio of resistance.
R1 = 40Ω
Further VNP = 20 V ⇒ VR = 69 - 20 = 49 V
R = $\frac{49}{3.5}$ = 19Ω
In the circuit shown in the figure:
Correct answer: option 2
In parallel current distribution in inverse ratio of resistance.
R1 = 40Ω
Further VNP = 20 V ⇒ VR = 69 - 20 = 49 V
R = $\frac{49}{3.5}$ = 19Ω