If $(\frac{x}{y}+1)=4$, then what is the value of $(\frac{x^2+y^2}{y^2})$ ?
Answer & explanation
Correct answer: option 4
If $(\frac{x}{y}+1)=4$,
then what is the value of $(\frac{x^2+y^2}{y^2})$ = ?
Put the value of x = 3 and y = 1
$(\frac{x^2+y^2}{y^2})$ = $(\frac{3^2+1^2}{1^2})$ = 10