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If $(\frac{x}{y}+1)=4$, then what is the value of $(\frac{x^2+y^2}{y^2})$ ? |
12 22 14 10 |
10 |
If $(\frac{x}{y}+1)=4$, then what is the value of $(\frac{x^2+y^2}{y^2})$ = ? Put the value of x = 3 and y = 1 $(\frac{x^2+y^2}{y^2})$ = $(\frac{3^2+1^2}{1^2})$ = 10 |
