Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $(\frac{x}{y}+1)=4$, then what is the value of $(\frac{x^2+y^2}{y^2})$ ?

Options:

12

22

14

10

Correct Answer:

10

Explanation:

If $(\frac{x}{y}+1)=4$,

then what is the value of $(\frac{x^2+y^2}{y^2})$ = ?

Put the value of x = 3 and y = 1

$(\frac{x^2+y^2}{y^2})$ = $(\frac{3^2+1^2}{1^2})$  = 10