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If x + \(\frac{1}{x}\) = 12 then find the value of x2 + \(\frac{1}{x^2}\) |
132 142 122 167 |
142 |
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 12, then ⇒ x2 + \(\frac{1}{x^2}\) = 122 - 2 = 142 |
