If x + \(\frac{1}{x}\) = 12 then find the value of  x2 + \(\frac{1}{x^2}\)

132 142 122 167

142

⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 12, then  ⇒ x2 + \(\frac{1}{x^2}\) = 122 - 2  = 142