Practicing Success
Practicing Success
CUET Preparation Today
If $x+\frac{1}{x}=3$, then the value of $x^2+\frac{1}{x^2}$ is |
9 11 7 3 |
7 |
$\left(x+\frac{1}{x}\right)^2=x^2+\frac{1}{x^2}+2×x×\frac{1}{x}$ $⇒(3)^2=x^2+\frac{1}{x^2}+2$ $9=x^2+\frac{1}{x^2}+2$ $⇒x^2+\frac{1}{x^2}=9-2=7$ |
