CUET Preparation Today
CUET
General Test
Quantitative Reasoning
Algebra
If $x+\frac{1}{x}=3$, then the value of $x^2+\frac{1}{x^2}$ is
9
11
7
3
$\left(x+\frac{1}{x}\right)^2=x^2+\frac{1}{x^2}+2×x×\frac{1}{x}$
$⇒(3)^2=x^2+\frac{1}{x^2}+2$
$9=x^2+\frac{1}{x^2}+2$
$⇒x^2+\frac{1}{x^2}=9-2=7$
