If $\frac{a}{4}$ = \(\frac{b}{9}\

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $\frac{a}{4}$ = $\frac{b}{9}$ = $\frac{c}{1}$

then find ( $\frac{a + b + c}{b + c }$ ).

Options:

$\frac{8}{5}$

$\frac{7}{5}$

$\frac{7}{6}$

$\frac{9}{5}$

Correct Answer:

$\frac{7}{5}$

Explanation:

Given, $\frac{a}{4}$ = $\frac{b}{9}$ = $\frac{c}{1}$

Here we can directly conclude that

a = 4, b = 9, c = 1, hence

⇒ ( $\frac{a + b + c}{b + c }$ ) = ( $\frac{4 + 9 + 1}{ 9 + 1 }$ )= $\frac{7}{5}$