If a/4 = b/9 = c/1 then find ( (a + b + c)/(b + c ) ).

Given, \(\frac{a}{4}\) = \(\frac{b}{9}\) = \(\frac{c}{1}\)

Here we can directly conclude that 

a = 4, b = 9, c = 1, hence

⇒ (\(\frac{a + b + c}{b + c }\)) = (\(\frac{4 + 9 + 1}{ 9 + 1 }\)) = \(\frac{7}{5}\)