If \(\frac{a}{4}\) = \(\frac{b}{9}\

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If \(\frac{a}{4}\) = \(\frac{b}{9}\) = \(\frac{c}{1}\)

then find (\(\frac{a + b + c}{b + c }\)).

Options:

\(\frac{8}{5}\)

\(\frac{7}{5}\)

\(\frac{7}{6}\)

\(\frac{9}{5}\)

Correct Answer:

\(\frac{7}{5}\)

Explanation:

Given, \(\frac{a}{4}\) = \(\frac{b}{9}\) = \(\frac{c}{1}\)

Here we can directly conclude that

a = 4, b = 9, c = 1, hence

⇒ (\(\frac{a + b + c}{b + c }\)) = (\(\frac{4 + 9 + 1}{ 9 + 1 }\))= \(\frac{7}{5}\)