Based on their rate laws, arrange the following reactions in the decreasing sequence of the reaction order. (A) Rate = $k [A]^{3/2} [B]^{-1}$ Choose the correct answer from the options given below: |
(A), (C), (B), (D) (D), (C), (B), (A) (D), (B), (C), (A) (B), (C), (A), (D) |
(D), (B), (C), (A) |
The correct answer is Option (3) → (D), (B), (C), (A) First, find the order of each reaction by adding the powers of concentrations in the rate law. Calculate reaction orders (A) $\text{Rate} = k[A]^{3/2}[B]^{-1}$ Order = $\frac{3}{2} - 1 = \frac{1}{2}$ (B) $\text{Rate} = k[\text{CHCl}_3][\text{Cl}_2]^{1/2}$ Order = $1 + \frac{1}{2} = \frac{3}{2}$ (C) $\text{Rate} = k[\text{CH}_3\text{COOC}_2\text{H}_5][\text{H}_2\text{O}]^{0}$ Order = 1 + 0 = 1 (D) $\text{Rate} = k[A]^{1/2}[B]^{3/2}$ Order = $\frac{1}{2} + \frac{3}{2} = 2$ Decreasing order of reaction order $(D)\; (2) > (B)\; (1.5) > (C)\; (1) > (A)\; (0.5)$ Correct answer: (D), (B), (C), (A) |