ABCD is a cyclic quadrilateral . Find the value of $y$ : |
116° 38° 64° 76° |
64° |
∠CDA = 180° - 116° = 64° ABCD is a cyclic quadrilateral, So, ∠CDA + ∠CBA = 180° ∠CBA = 180° - 64° ∠CBA = 116° Now, ∠OBC + ∠OBA = 116° 52° + ∠OBA = 116° ∠OBA = 116° - 52° = 64° The correct answer is option (2) : 64° |