Practicing Success
For the reaction A Products, it is found that the rate of reaction increases by a factor of 6.25, when the concentration of A is increased by a factor of 2.5. The order of reaction with respect to A is: |
0.5 1 2 3 |
2 |
The order of the reaction with respect to A, denoted as "n," can be determined by the given information: \[\frac{{\text{{rate}}_2}}{{\text{{rate}}_1}} = \left(\frac{{[\text{{A}}]_2}}{{[\text{{A}}]_1}}\right)^n\] Substituting the values provided: \[\frac{{6.25}}{{1}} = \left(\frac{{2.5}}{{1}}\right)^n\] Simplifying the equation: \[2.5^n = 6.25\] Taking the logarithm of both sides: \[n \log(2.5) = \log(6.25)\] Solving for "n": \[n = \frac{{\log(6.25)}}{{\log(2.5)}}\] Using a calculator, we find \(n \approx 2\). Hence, the order of the reaction with respect to A is 2. |