If cos 53^°=x/y, then sec 53^°+cot 37^° is equal to:

$\frac{x+\sqrt{y^2-x^2}}{y}$

$\frac{x+\sqrt{y^2-x^2}}{x}$

$\frac{y+\sqrt{y^2-x^2}}{x}$

$\frac{y+\sqrt{y^2-x^2}}{y}$