Write the correct IUPAC name of the compound ‘x’ given below:
CH3–CO–CH2–CH2–COOH
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 4-Oxopentanoic acid
The compound has two functional groups, a carboxylic acid and a ketone. The carboxylic acid is the principal group: it gives the suffix “-oic acid” and its carbon is C-1. The ketone is then named as a prefix, oxo.
5CH3–4CO–3CH2–2CH2–1COOH
The chain has five carbons (pentanoic acid) and the C=O is on C-4: 4-Oxopentanoic acid.