Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Continuity and Differentiability

Question:
Define a function $f:\mathbb{R}\rightarrow \mathbb{R}$ as $f(x)=\begin{cases}\frac{x}{|x|}& \text{if}\hspace{.2cm} x <0\\ -1 & \text{otherwise} \end{cases}$. Then $f$ is
Options:
A continuous function
Discontinuous at 0
Continuous everywhere except 0
None of the above
Correct Answer:
A continuous function
Explanation:
$f$ is continuous at $x=0$ because $\lim_{x \to 0}f(x)=-1=f(0)$ and it is continuous everywhere else.