Let $y\left(x\right)$ be the gene

CUET Preparation Today

Start Free Mocks

Home Questions YMG5NMG952

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Let $y\left(x\right)$ be the general solution of $x^{5}\frac{dy}{dx}=-y^5$. Let $y\left(1\right)=1$ then

Options:

$\frac{1}{x^4}-\frac{1}{y^4}=1$

$\frac{1}{x^4}+\frac{1}{y^4}=2$

$\frac{1}{x^4}=1+\frac{1}{y^3}$

$\frac{1}{x^4}-\frac{1}{y^4}=2$

Correct Answer:

$\frac{1}{x^4}+\frac{1}{y^4}=2$

Explanation:

Given differential equation is separable