An unknown gas ‘$X$’ is dissolved in water at $2.5\text{ bar}$ pressure and has mole fraction $0.04$ in solution. The mole fraction of ‘$X$’ gas when the pressure of gas is doubled at the same temperature is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $0.08$ ##
Mole fraction of gas X in solution $= 0.04$
$\text{Pressure} = 2.5\text{ bar}$
$\text{Let } P_1 = P^0 x_1$
$2.5 = 0.04\ P^0 \dots\text{(i)}$
$\text{Let pressure be doubled, then } P_2$
$5.0 = x_2 P^0 \dots\text{(ii)}$
Dividing Eqn (ii) by Eqn (i), we get
$\frac{5.0}{2.5} = \frac{x_2}{0.04}$
$2 \times 0.04 = x_2$
$x_2 = 0.08$