An unknown gas ‘$X$’ is dissolved in water at $2.5\text{ bar}$ pressure and has mole fraction $0.04$ in solution. The mole fraction of ‘$X$’ gas when the pressure of gas is doubled at the same temperature is

$0.08$

The correct answer is Option (1) → $0.08$ ##

Mole fraction of gas X in solution $= 0.04$

$\text{Pressure} = 2.5\text{ bar}$

$\text{Let } P_1 = P^0 x_1$

$2.5 = 0.04\ P^0 \dots\text{(i)}$

$\text{Let pressure be doubled, then } P_2$

$5.0 = x_2 P^0 \dots\text{(ii)}$

Dividing Eqn (ii) by Eqn (i), we get

$\frac{5.0}{2.5} = \frac{x_2}{0.04}$

$2 \times 0.04 = x_2$

$x_2 = 0.08$