An alternating voltage $V = V_0\sin (ωt + π/2)$ is applied across an ac circuit. As a result, a current $I = I_0\sin (ωt + π/6)$ flows in it. The power factor of the circuit is

0.5

The correct answer is Option (2) → 0.5

$\text{Given: } V = V_0 \sin(\omega t + \pi/2),~ I = I_0 \sin(\omega t + \pi/6)$

$\text{Phase difference: } \phi = (\pi/2) - (\pi/6) = \pi/3$

$\text{Power factor: } \text{pf} = \cos \phi = \cos(\pi/3)$

$\text{pf} = 0.5$

$\text{Answer: Power factor } = 0.5$