How many moles of sodium hydroxide are present in 2.5 L of a 0.5 M aqueous solution?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 1.25
Molarity is the number of moles of solute in one litre of solution, so the moles of solute are molarity times volume in litres.
\( \displaystyle n=M\times V \)
\( \displaystyle n=0.5\,\mathrm{mol\,L^{-1}}\times 2.5\,\mathrm{L} \)
\( \displaystyle n=1.25\,\mathrm{mol} \)