The area of the region bounded by the curve $y=x^2+2, y=-x, x=0$ and x=1 is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{17}{6}$
so area = $\int\limits_0^1x^2+2dx+\frac{1}{2}×1×1$
$=\left[\frac{x^3}{x}+2x\right]_0^1+\frac{1}{2}$
$=\frac{7}{3}+\frac{1}{2}=\frac{17}{6}$