CUET Preparation Today
What is the area (in sq cm) of an equilateral triangle of side 35 cm? |
\(\frac{484}{4}\)\(\sqrt{3}\) \(\frac{625}{4}\)\(\sqrt{3}\) \(\frac{1225}{4}\)\(\sqrt{3}\) \(\frac{1228}{4}\)\(\sqrt{3}\) |
\(\frac{1225}{4}\)\(\sqrt{3}\) |
Area of equilateral triangle = \(\frac{ \sqrt{3}}{4}\)a2 = \(\frac{ \sqrt{3}}{4}\) × 35 × 35 = \(\frac{1225}{4}\)\(\sqrt{3}\) cm2 |
