The corner points of feasible region determined by the following system of linear inequalities:

$2x+y≤10, x+3y≤15, x≥0, y≥0$ are $(0, 0), (5, 0), (3, 4)$ and $(0, 5)$

Let $ z= px +qy ,$ when $p, q > 0$ then the relation between p and q, so that maximum of z occurs at both points $(3, 4)$ and $(0, 5)$ is :

$3p=q$