If tanθ - cotθ = 7 , find the value of tan2θ + cot2θ .
Answer & explanation
Correct answer: option 3
Formula I → [ tanθ = \(\frac{1}{cotθ}\)]
Formula II → [If x - \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 + 2]
tanθ - \(\frac{1}{tanθ}\) = 7
⇒ tan2θ + \(\frac{1}{tan^2θ}\) = (7)2 + 2
⇒ tan2θ + cot2θ = 49 + 2 = 51