If tanθ - cotθ = 7 , find the value of tan2θ + cot2θ . |
55 47 51 49 |
51 |
Formula I → [ tanθ = \(\frac{1}{cotθ}\)] Formula II → [If x - \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 + 2] tanθ - \(\frac{1}{tanθ}\) = 7 ⇒ tan2θ + \(\frac{1}{tan^2θ}\) = (7)2 + 2 ⇒ tan2θ + cot2θ = 49 + 2 = 51 |