By using equations of the line \(\displaystyle\frac{x+1}{2}=\frac{y}{3}=\frac{z-3}{6}\) and the plane \(10x+2y-11z-3=0\), answer the following questions.
The plane 10x + 2y − 11z − 3 = 0 intersects the Z-axis at the point
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \(\left(0,0,-\displaystyle\frac{3}{11}\right)\)
Every point of the z-axis has x = 0 and y = 0. Putting these in the equation of the plane:
\(10(0) + 2(0) - 11z - 3 = 0\)
\(-11z = 3\)
\( \displaystyle z = -\frac{3}{11} \)
So the point is \(\left(0, 0, -\frac{3}{11}\right)\).
Note: This topic was not in the CUET 2026 syllabus.