By using equations of the line $\frac{x+1}{2}=\frac{y}{3}=\frac{z-3}{6}$ and the plane $10 x+2 y-11 z-3=0$, answer the following questions.
The plane 10x + 2y – 11z – 3 = 0 intersect the Z-axis at the point
Answer & explanation
Correct answer: option 4
at z-axis , x = 0 , y = 0
so 10(0) + 2(0) - 11z - 3 =0
so -11z - 3 = 0
z = $\frac{-3}{11}$
(x, y, z) = $\left(0,0,-\frac{3}{11}\right)$ → intersection with z-axis
Option: D