Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:

The solution of the differential equation : \(\frac{dx}{x} + \frac{dy}{y}\) = 0 is :

Options:

\(\frac{1}{x} + \frac{1}{y}\) = c

xy = C

x + y = c

log x . log y = c

Correct Answer:

xy = C

Explanation:

\(\frac{dx}{x} + \frac{dy}{y}\) = 0

\(\frac{dx}{x} =- \frac{dy}{y}\) 

log x = - log y + log C

xy = C