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Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(III), (C)-(I), (D)-(II) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) |
(A)-(III), (B)-(IV), (C)-(II), (D)-(I) |
The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Matching List-I with List-II: (A) The maximum value of \( f(x) = \sin(3x) + 6 \) The maximum value of \( \sin(3x) \) is 1, so maximum value of \( f(x) = 1 + 6 = \mathbf{7} \) (B) The maximum value of \( f(x) = -|x + 2| + 4 \) The minimum value of \( |x + 2| \) is 0 (when \( x = -2 \)), so maximum of \( f(x) = -0 + 4 = \mathbf{4} \) (C) The minimum value of \( f(x) = (3x + 1)^2 + 5 \) The minimum value of a square is 0, so minimum of \( f(x) = 0 + 5 = \mathbf{5} \) (D) The minimum value of \( f(x) = 2\cos x + 4 \) Minimum of \( \cos x \) is -1, so minimum of \( f(x) = 2(-1) + 4 = \mathbf{2} \) |
