A tower stands vertically on the ground. From a point on the ground which is 18 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 30°. Find the height of the tower.

$6\sqrt{3}m$

Tan 30 = Height of tower/Horizontal Distance between foot of tower and the point of observation

Tan 30 = H/18

H = 18*1/√3 = $18\sqrt{3}m$/3 = $6\sqrt{3}m$

The correct answer is option (2) : $6\sqrt{3}m$