The price of an article was increased two times successively by 10%. By what percent should the new price be reduced so as to restore the original price?

17.36%

10% = \(\frac{1}{10}\)

Let number = 100

After increasing by 10% successively, the number = 100 × \(\frac{11}{10}\) × \(\frac{11}{10}\) = 121

To restore number should be decreased by = 121 - 100 = 21

Decreasing percentage = \(\frac{21}{121}\) × 100 = 17.36%