Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

Match List I with List II

LIST I

LIST II

A. Maximum value of $f(x) = -|x+1|+3$

I. 6

B. Minimum value of $f(x) = (2x − 1)^2 + 5$

II. 5

C. Maximum value of $f(x) = 6 – x^2$

III. no maximum value

D. Maximum value of $f(x) = x^3 + 1$

IV. 3

Choose the correct answer from the options given below:

Options:

A-IV, B-II, C-I, D-III

A-III, B-IV, C-I, D-II

A-I, B-II, C-III, D-IV

A-II, B-III, C-IV, D-I

Correct Answer:

A-IV, B-II, C-I, D-III

Explanation:

(A) $f(x) = -|x+1|+3$

maximum value is 3 when $x = -1$

(B) $f(x) = (2x − 1)^2 + 5$

minimum value is 5 at $x = \frac{-1}{2}$

(C) $f(x) = 6 – x^2$

maximum value is 6 at x = 0

(D) $f(x) = x^3 + 1$

This function is always increasing ⇒ No maximum value