Let f(x) = cos x and g(x) = [x + 1], where [.] denotes the greatest integer function. They, (gof)' (π/2), is |
0 1 -1 non-existant |
non-existant |
We have, f(x) = cos x and g(x) = [x + 2] ∴ gof(x) = g(f(x)) = [cos x + 2] $\Rightarrow gof(x)= \begin{cases}2, & \text { if } 0<x \leq \pi / 2 \\ 1, & \text { if } \pi / 2 \leq x<\pi\end{cases}$ We have, $\lim\limits_{x \rightarrow \pi / 2^{-}} gof(x)=2$ and $\lim\limits_{x \rightarrow \pi / 2^{+}} gof(x)=1$ Clearly, gof(x) is not continuous at $x=\frac{\pi}{2}$. Hence, it is not differentiable at x = π/ 2. Consequently, (gof)'(π/2) does not exist. |