Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Let f(x) = cos x and g(x) = [x + 1], where [.] denotes the greatest integer function. They, (gof)' (π/2), is

Options:

0

1

-1

non-existant

Correct Answer:

non-existant

Explanation:

We have, f(x) = cos x and g(x) = [x + 2]

∴  gof(x) = g(f(x)) = [cos x + 2]

$\Rightarrow gof(x)= \begin{cases}2, & \text { if } 0<x \leq \pi / 2 \\ 1, & \text { if } \pi / 2 \leq x<\pi\end{cases}$

We have,

$\lim\limits_{x \rightarrow \pi / 2^{-}} gof(x)=2$  and $\lim\limits_{x \rightarrow \pi / 2^{+}} gof(x)=1$

Clearly, gof(x) is not continuous at $x=\frac{\pi}{2}$.

Hence, it is not differentiable at x = π/ 2.

Consequently, (gof)'(π/2) does not exist.