If A and B are independent events with \(P(A)=0.8\) and \(P(B)=0.4\), then the value of \(P(A \cup B)\) is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 0.88
For independent events, \(P(A \cap B) = P(A)\,P(B)\):
\(P(A \cap B) = 0.8 \times 0.4 = 0.32\)
By the addition rule:
\(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
\(= 0.8 + 0.4 - 0.32 = 0.88\)