A does half as much work as B in one-sixth of the time. If together they take 10 days to complete a work. How much time shall B alone take to do it ?
Answer & explanation
Correct answer: option 1
A × 1/6 = B × 1/2
Efficiency of A : B = 3 : 1
Total work = Efficiency × Time
= ( 3 + 1 ) × 10
= 40
Time taken by B alone to complete the work = 40/1
= 40 days
The correct answer is option (1) : 40 days