Practicing Success
A train leaves station A at 6 AM and reaches station B at 10 AM on the same day. Another train leaves station B at 8 AM and reaches station A at 11:30 AM on the same day. The time at which the two trains meet is: |
7:56 AM 8:56 AM 8:14 AM 8:26 AM |
8:56 AM |
LCM of 4 and 3.5 = 28 Let distance = 28 km SA = \(\frac{28}{4}\) = 7 km/hr SB = \(\frac{28}{3.5}\) = 8 km/hr From 6 AM to 8 AM, A runs alone, in first 2 hours it travels = 14 km After 8 am: Relative speed = 7 + 8 = 15 km/hr Time taken to meet after 8 am = \(\frac{Remaining\;Distance}{Relative\;speed}\) = \(\frac{14}{15}\) = 56 mins So at ⇒ 8:56 AM both the trains meet. |