If Shivan walks at the rate of 19 km/h. How much time (in minutes) will he take to cover 665 m?

$2\frac{1}{10}$

Given :-

Speed of Shivam = 19 km/h

19 km/h = 19 × \(\frac{5}{18}\) m/sec  = × \(\frac{95}{18}\) m/sec 

Distance = 665 m

Time taken = × \(\frac{665 × 18 }{95}\) m/sec 

= 126 sec

Time in minute = \(\frac{126}{60}\) = 2\(\frac{1}{10}\) min