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The probability that a leap year selected at random will have 53 Mondays is |
$\frac{1}{7}$ $\frac{2}{7}$ $\frac{3}{7}$ $\frac{4}{7}$ |
$\frac{2}{7}$ |
The correct answer is Option (2) → $\frac{2}{7}$ ** A leap year has 366 days = 52 weeks + 2 days Thus, there are always 52 Mondays, and 53 Mondays occur only if one of the two extra days is Monday. The two extra days can be: Sunday–Monday, Monday–Tuesday, Tuesday–Wednesday, Wednesday–Thursday, Thursday–Friday, Friday–Saturday, or Saturday–Sunday. Out of these 7 possibilities, 2 include Monday (Sunday–Monday and Monday–Tuesday). Hence, $P(\text{53 Mondays}) = \frac{2}{7}$ $\frac{2}{7}$ |
