CUET Preparation Today
CUET
-- Mathematics - Section A
Definite Integration
The value of the integral $I=\int\limits^{3}_{-3}(x^3-x)dx $ is :
0
$\frac{3}{2}$
$-\frac{1}{2}$
$\frac{x^4}{4}-\frac{x^2}{2}+C$
The correct answer is Option (1) → 0
$\int\limits_{-3}^3(x^3-x)dx=0$ $(x^3-x)$ odd function
