Practicing Success
Practicing Success
CUET Preparation Today
The point on the curve $x^2=2 y$ in the I quadrant which is nearest to the point (0, 5) is: |
$(2 \sqrt{2}, 0)$ $(0,0)$ $(2 \sqrt{2}, 4)$ $(2,2)$ |
$(2 \sqrt{2}, 4)$ |
The correct answer is Option (3) → $(2 \sqrt{2}, 4)$ |
