The function $f(x)=3x^2$ is : |
increasing in(-∞, -1) ∪ (1, ∞) decreasing in (-∞, -1) ∪ (1, ∞) and increasing in (-1, 1) increasing in (0, ∞) and decreasing in (-∞, 0) decreasing in (0,-1) |
increasing in (0, ∞) and decreasing in (-∞, 0) |
The correct answer is option (3) → increasing in (0, ∞) and decreasing in (-∞, 0) $f(x)=3x^2$ so $f'(x)=6x=0⇒x=0$ $f(x)$ = increasing in(-∞, -1) ∪ (1, ∞) |