Shyam walks 4 km north-east and then 3 km south-east. Find the total distance as well as the shortest distance between starting and end point.

7, 5

The correct answer is Option (3) → 7, 5

Total distance = 4 km + 3 km = 7 km

Shortest distance = in triangle OAB (AS PER GIVEN IMAGE)

OAB

OB² = OA² + AB²

       = 4² + 3²

       = 16 + 9

       = 25

OB  = 5 KM