Match the properties given in list-I with the metals given in list-II
|
List-I Property |
List-II Metal |
|
(A) Element with highest second ionization enthalpy |
(I) Co |
|
(B) Element with highest heat of atomisation |
(II) Cu |
|
(C) M in \( M(CO)_6 \) |
(III) Zn |
|
(D) Element with highest third ionization enthalpy |
(IV) Cr |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Ionisation enthalpies are unusually high when the electron has to be removed from a stable (half-filled or completely filled) d subshell, and the enthalpy of atomisation is high when the atom has many unpaired electrons for metal–metal bonding.
(A) Element with highest second ionization enthalpy — This matches (II) Cu. Cu (Z = 29) is [Ar]3d104s1; the first electron leaves 4s and gives \( \ce{Cu^{+}} \): 3d10. The second electron must come out of this completely filled 3d10 set, so ΔiH2 of Cu (1958 kJ mol−1) is the highest.
(B) Element with highest heat of atomisation — This matches (I) Co. ΔaH°: Co 425, Cr 397, Cu 339, Zn 126 kJ mol−1; Zn has no unpaired d electrons for bonding and is the lowest.
(C) M in M(CO)6 — This matches (IV) Cr. Hexacarbonylchromium(0), \( \ce{Cr(CO)6} \), is the octahedral homoleptic carbonyl; Ni forms \( \ce{Ni(CO)4} \) and Fe forms \( \ce{Fe(CO)5} \).
(D) Element with highest third ionization enthalpy — This matches (III) Zn. Zn (Z = 30) is [Ar]3d104s2; removing the two 4s electrons gives \( \ce{Zn^{2+}} \): 3d10. The third electron must break the full 3d10 set, so ΔiH3 of Zn (3837 kJ mol−1) is the highest.
Shortcut: (A)-(II) appears in Options (1) and (2), and (B)-(I) leaves only Option (2).
Note: The same/similar question has been asked in different years by NTA as per the details given below:
| 2026 | 2025 | 2024 | 2023 | 2022 |
|---|---|---|---|---|
| – | 23-05 S2 | – | 07-06 S3 | – |