A random variable X has the following probability distribution :
| X | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X) | $C$ | $2C$ | $2C$ | $3C$ | $C^2$ | $2C^2$ | $7C^2+C$ |
Then the value of C is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{10}$
$∑P(X)=1$
$9C+10C^2=1$
so $10C^2+9C-1=0$
$10C^2+10C-C-1⇒(10C-1)(C+1)=0$
$C≠-1$
so $C=\frac{1}{10}$