Practicing Success
Practicing Success
CUET Preparation Today
If \(A=\left[\begin{array}{ll}a & b\\ b& a\end{array}\right]\) and \(A^2=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right]\) then |
\(\alpha=a^2+b^2,\beta=ab\) \(\alpha=a^2+b^2,\beta=2ab\) \(\alpha=a^2+b^2,\beta=a^2-b^2\) \(\alpha=2ab,\beta=a^2+b^2\) |
\(\alpha=a^2+b^2,\beta=2ab\) |
\(A^2=\left[\begin{array}{ll}a & b\\ b& a\end{array}\right]\left[\begin{array}{ll}a & b\\ b& a\end{array}\right]=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right]\) $⇒\begin{bmatrix}a^2+b^2&2ab\\2ab&a^2+b^2\end{bmatrix}=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right]$ $\alpha=a^2+b^2$ $\beta=2ab$ |
