If a person travels at a speed of 48 km/h, he will reach his destination on time. He covers two-thirds of his journey in five-sixths of time. At what speed (in km/h) should he travel to cover the remaining distance to reach his destination on time?
Answer & explanation
Correct answer: option 2
Let Time = 6t
Speed = 48 km/h
Distance = Speed × Time
= 48 × 6t = 288t
According to question ,
\(\frac{1}{3}\)rd of 288t = 96t
\(\frac{1}{6}\)th of 6t = t
Speed to cover remaining 96t distance = \(\frac{96t}{t}\) = 96 km/h