If a person travels at a speed of 48 km/h, he will reach his destination on time. He covers two-thirds of his journey in five-sixths of time. At what speed (in km/h) should he travel to cover the remaining distance to reach his destination on time?

96

Let Time = 6t

Speed = 48 km/h

Distance = Speed × Time

= 48 × 6t = 288t

According to question ,

\(\frac{1}{3}\)rd of 288t = 96t

\(\frac{1}{6}\)th of 6t = t

Speed to cover remaining 96t distance = \(\frac{96t}{t}\) = 96 km/h