Practicing Success
The vector equation of the line passing through the points (4,2,3) and which is parallel to the vector i +2j -5k is given by- |
(4+λ)i + 2(1+λ)j + (3-5λ) k (4+λ)i - 2(1+λ)j + (3-5λ) k (4+λ)i + 2(1+λ)j + (3+5λ) k (4-λ)i + 2(1-λ)j + (3-5λ) k |
(4+λ)i + 2(1+λ)j + (3-5λ) k |
We have vector a = 4i+ 2j +3k and vector b= i+2j -5k Therefore the vector equation of the line is vector r = a + λb ⇒ r = (4i+ 2j +3k ) + λ (i+2j -5k) ⇒ r = (4+λ)i + 2(1+λ)j + (3-5λ) k
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