If sec 2x = cosec (x - 45°) where x is an acute angle find the value of x.
Answer & explanation
Correct answer: option 4
We know that if sec A = cosec B, then A + B = 90°
ATQ,
sec 2x = cosec (x-45°)
⇒ 2x + x - 45° = 90°
⇒ 3x = 135°
⇒ x = 45°
If sec 2x = cosec (x - 45°) where x is an acute angle find the value of x.
Correct answer: option 4
We know that if sec A = cosec B, then A + B = 90°
ATQ,
sec 2x = cosec (x-45°)
⇒ 2x + x - 45° = 90°
⇒ 3x = 135°
⇒ x = 45°